7y+3(y-9)=6(y+1)-4

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Solution for 7y+3(y-9)=6(y+1)-4 equation: 



7y+3(y-9)=6(y+1)-4

We move all terms to the left:

7y+3(y-9)-(6(y+1)-4)=0

We multiply parentheses

7y+3y-(6(y+1)-4)-27=0



We calculate terms in parentheses: -(6(y+1)-4), so:

6(y+1)-4

We multiply parentheses

6y+6-4

We add all the numbers together, and all the variables

6y+2

Back to the equation:

-(6y+2)



We add all the numbers together, and all the variables

10y-(6y+2)-27=0

We get rid of parentheses

10y-6y-2-27=0

We add all the numbers together, and all the variables

4y-29=0

We move all terms containing y to the left, all other terms to the right

4y=29

y=29/4

y=7+1/4

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