7y+3(y-8)=24(y+1)-3

Solution for 7y+3(y-8)=24(y+1)-3 equation:

7y+3(y-8)=24(y+1)-3

We move all terms to the left:

7y+3(y-8)-(24(y+1)-3)=0

We multiply parentheses

7y+3y-(24(y+1)-3)-24=0


We calculate terms in parentheses: -(24(y+1)-3), so:

24(y+1)-3

We multiply parentheses

24y+24-3

We add all the numbers together, and all the variables

24y+21

Back to the equation:

-(24y+21)


We add all the numbers together, and all the variables

10y-(24y+21)-24=0

We get rid of parentheses

10y-24y-21-24=0

We add all the numbers together, and all the variables

-14y-45=0

We move all terms containing y to the left, all other terms to the right

-14y=45

y=45/-14

y=-3+3/14