7y+3(y-5)=(y+2)-2

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Solution for 7y+3(y-5)=(y+2)-2 equation: 



7y+3(y-5)=(y+2)-2

We move all terms to the left:

7y+3(y-5)-((y+2)-2)=0

We multiply parentheses

7y+3y-((y+2)-2)-15=0



We calculate terms in parentheses: -((y+2)-2), so:

(y+2)-2

We get rid of parentheses

y+2-2

We add all the numbers together, and all the variables

y

Back to the equation:

-(y)



We add all the numbers together, and all the variables

9y-15=0

We move all terms containing y to the left, all other terms to the right

9y=15

y=15/9

y=1+2/3

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