7y+3(y-4)=3(y+1)-2

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Solution for 7y+3(y-4)=3(y+1)-2 equation:


Simplifying
7y + 3(y + -4) = 3(y + 1) + -2

Reorder the terms:
7y + 3(-4 + y) = 3(y + 1) + -2
7y + (-4 * 3 + y * 3) = 3(y + 1) + -2
7y + (-12 + 3y) = 3(y + 1) + -2

Reorder the terms:
-12 + 7y + 3y = 3(y + 1) + -2

Combine like terms: 7y + 3y = 10y
-12 + 10y = 3(y + 1) + -2

Reorder the terms:
-12 + 10y = 3(1 + y) + -2
-12 + 10y = (1 * 3 + y * 3) + -2
-12 + 10y = (3 + 3y) + -2

Reorder the terms:
-12 + 10y = 3 + -2 + 3y

Combine like terms: 3 + -2 = 1
-12 + 10y = 1 + 3y

Solving
-12 + 10y = 1 + 3y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-3y' to each side of the equation.
-12 + 10y + -3y = 1 + 3y + -3y

Combine like terms: 10y + -3y = 7y
-12 + 7y = 1 + 3y + -3y

Combine like terms: 3y + -3y = 0
-12 + 7y = 1 + 0
-12 + 7y = 1

Add '12' to each side of the equation.
-12 + 12 + 7y = 1 + 12

Combine like terms: -12 + 12 = 0
0 + 7y = 1 + 12
7y = 1 + 12

Combine like terms: 1 + 12 = 13
7y = 13

Divide each side by '7'.
y = 1.857142857

Simplifying
y = 1.857142857

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