7y+29=3(2y+3)

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Solution for 7y+29=3(2y+3) equation:



7y+29=3(2y+3)
We move all terms to the left:
7y+29-(3(2y+3))=0
We calculate terms in parentheses: -(3(2y+3)), so:
3(2y+3)
We multiply parentheses
6y+9
Back to the equation:
-(6y+9)
We get rid of parentheses
7y-6y-9+29=0
We add all the numbers together, and all the variables
y+20=0
We move all terms containing y to the left, all other terms to the right
y=-20

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