7y+22=4(y-2)

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Solution for 7y+22=4(y-2) equation:



7y+22=4(y-2)
We move all terms to the left:
7y+22-(4(y-2))=0
We calculate terms in parentheses: -(4(y-2)), so:
4(y-2)
We multiply parentheses
4y-8
Back to the equation:
-(4y-8)
We get rid of parentheses
7y-4y+8+22=0
We add all the numbers together, and all the variables
3y+30=0
We move all terms containing y to the left, all other terms to the right
3y=-30
y=-30/3
y=-10

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