7y+22+6y-3=6(9+y)+14

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Solution for 7y+22+6y-3=6(9+y)+14 equation: 



7y+22+6y-3=6(9+y)+14

We move all terms to the left:

7y+22+6y-3-(6(9+y)+14)=0

We add all the numbers together, and all the variables

7y+6y-(6(y+9)+14)+22-3=0

We add all the numbers together, and all the variables

13y-(6(y+9)+14)+19=0



We calculate terms in parentheses: -(6(y+9)+14), so:

6(y+9)+14

We multiply parentheses

6y+54+14

We add all the numbers together, and all the variables

6y+68

Back to the equation:

-(6y+68)



We get rid of parentheses

13y-6y-68+19=0

We add all the numbers together, and all the variables

7y-49=0

We move all terms containing y to the left, all other terms to the right

7y=49

y=49/7

y=7

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