7y+20=2(3y+1)

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Solution for 7y+20=2(3y+1) equation: 



7y+20=2(3y+1)

We move all terms to the left:

7y+20-(2(3y+1))=0



We calculate terms in parentheses: -(2(3y+1)), so:

2(3y+1)

We multiply parentheses

6y+2

Back to the equation:

-(6y+2)



We get rid of parentheses

7y-6y-2+20=0

We add all the numbers together, and all the variables

y+18=0

We move all terms containing y to the left, all other terms to the right

y=-18

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