7y+19=3(y-3)

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Solution for 7y+19=3(y-3) equation: 



7y+19=3(y-3)

We move all terms to the left:

7y+19-(3(y-3))=0



We calculate terms in parentheses: -(3(y-3)), so:

3(y-3)

We multiply parentheses

3y-9

Back to the equation:

-(3y-9)



We get rid of parentheses

7y-3y+9+19=0

We add all the numbers together, and all the variables

4y+28=0

We move all terms containing y to the left, all other terms to the right

4y=-28

y=-28/4

y=-7

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