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7x^2=343
We move all terms to the left:
7x^2-(343)=0
a = 7; b = 0; c = -343;
Δ = b2-4ac
Δ = 02-4·7·(-343)
Δ = 9604
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9604}=98$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-98}{2*7}=\frac{-98}{14} =-7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+98}{2*7}=\frac{98}{14} =7 $
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