7x2=168+35x

Solution for 7x2=168+35x equation:

7x^2=168+35x

We move all terms to the left:

7x^2-(168+35x)=0

We add all the numbers together, and all the variables

7x^2-(35x+168)=0

We get rid of parentheses

7x^2-35x-168=0

a = 7; b = -35; c = -168;
Δ = b2-4ac
Δ = -352-4·7·(-168)
Δ = 5929
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5929}=77$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-77}{2*7}=\frac{-42}{14}
=-3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+77}{2*7}=\frac{112}{14}
=8
$