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7x^2-96x-28=0
a = 7; b = -96; c = -28;
Δ = b2-4ac
Δ = -962-4·7·(-28)
Δ = 10000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{10000}=100$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-96)-100}{2*7}=\frac{-4}{14} =-2/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-96)+100}{2*7}=\frac{196}{14} =14 $
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