7x2-4=5

Solution for 7x2-4=5 equation:

7x^2-4=5

We move all terms to the left:

7x^2-4-(5)=0

We add all the numbers together, and all the variables

7x^2-9=0

a = 7; b = 0; c = -9;
Δ = b2-4ac
Δ = 02-4·7·(-9)
Δ = 252
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{252}=\sqrt{36*7}=\sqrt{36}*\sqrt{7}=6\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{7}}{2*7}=\frac{0-6\sqrt{7}}{14}
=-\frac{6\sqrt{7}}{14}
=-\frac{3\sqrt{7}}{7}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{7}}{2*7}=\frac{0+6\sqrt{7}}{14}
=\frac{6\sqrt{7}}{14}
=\frac{3\sqrt{7}}{7}
$