If it's not what You are looking for type in the equation solver your own equation and let us solve it.
7x^2-36x-36=0
a = 7; b = -36; c = -36;
Δ = b2-4ac
Δ = -362-4·7·(-36)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2304}=48$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-48}{2*7}=\frac{-12}{14} =-6/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+48}{2*7}=\frac{84}{14} =6 $
| 5x+2=-3+2x+14 | | 2x(3)=5x-3/4 | | 120=-8(x-8) | | 6x+8=2(3x-4 | | 9.8x=-80.36 | | 3(3x+4)=21x+8 | | 1x-42.041=23.24 | | 59=23-4x | | 448+a/6=90 | | 31x1-12=18 | | -2a+29=17 | | -21x1=-4 | | 100/5=28/x | | 46=6-4w | | 28/x=5/100 | | 4(r-2)=13 | | -16=31x-21 | | 14+3x+24=20 | | x/28=5/100 | | 2(q−8)=4 | | 1/4x+1/2x+5=11 | | 4{r-2}=12 | | 1x+1/2=1 | | -3a+36=21 | | -9=26-5x | | 1+1.80x=2 | | 1x1=1/3 | | 2w-9w=35 | | m+3=-m-3 | | x+56=2(4x+7) | | 8-12x-3=-49 | | 2c+9=24 |