7x2+8x-10x=11

Solution for 7x2+8x-10x=11 equation:

7x^2+8x-10x=11

We move all terms to the left:

7x^2+8x-10x-(11)=0

We add all the numbers together, and all the variables

7x^2-2x-11=0

a = 7; b = -2; c = -11;
Δ = b2-4ac
Δ = -22-4·7·(-11)
Δ = 312
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{312}=\sqrt{4*78}=\sqrt{4}*\sqrt{78}=2\sqrt{78}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{78}}{2*7}=\frac{2-2\sqrt{78}}{14}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{78}}{2*7}=\frac{2+2\sqrt{78}}{14}
$