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7x^2+5x+4x=-1
We move all terms to the left:
7x^2+5x+4x-(-1)=0
We add all the numbers together, and all the variables
7x^2+9x+1=0
a = 7; b = 9; c = +1;
Δ = b2-4ac
Δ = 92-4·7·1
Δ = 53
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{53}}{2*7}=\frac{-9-\sqrt{53}}{14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{53}}{2*7}=\frac{-9+\sqrt{53}}{14} $
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