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7x^2+21x-70-12x-18=0
We add all the numbers together, and all the variables
7x^2+9x-88=0
a = 7; b = 9; c = -88;
Δ = b2-4ac
Δ = 92-4·7·(-88)
Δ = 2545
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{2545}}{2*7}=\frac{-9-\sqrt{2545}}{14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{2545}}{2*7}=\frac{-9+\sqrt{2545}}{14} $
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