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7x^2+12x=-5
We move all terms to the left:
7x^2+12x-(-5)=0
We add all the numbers together, and all the variables
7x^2+12x+5=0
a = 7; b = 12; c = +5;
Δ = b2-4ac
Δ = 122-4·7·5
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-2}{2*7}=\frac{-14}{14} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+2}{2*7}=\frac{-10}{14} =-5/7 $
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