7x/6+x=2-(x+1)/8

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Solution for 7x/6+x=2-(x+1)/8 equation: 



7x/6+x=2-(x+1)/8

We move all terms to the left:

7x/6+x-(2-(x+1)/8)=0

We add all the numbers together, and all the variables

x+7x/6-(2-(x+1)/8)=0

We calculate fractions


56x^2/()+x+(-(2-(x+1)*6)/()=0



We calculate terms in parentheses: +(-(2-(x+1)*6)/(), so:

-(2-(x+1)*6)/(

We multiply all the terms by the denominator


-(2-(x+1)*6)



We calculate terms in parentheses: -(2-(x+1)*6), so:

2-(x+1)*6

determiningTheFunctionDomain
-(x+1)*6+2

We multiply parentheses

-6x-6+2

We add all the numbers together, and all the variables

-6x-4

Back to the equation:

-(-6x-4)



We get rid of parentheses

6x+4

Back to the equation:

+(6x+4)



We get rid of parentheses

56x^2/()+x+6x+4=0

We multiply all the terms by the denominator


56x^2+x*()+6x*()+4*()=0

We add all the numbers together, and all the variables

56x^2+x*()+6x*()=0

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