7x/4=(8x+2)/3

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Solution for 7x/4=(8x+2)/3 equation: 



7x/4=(8x+2)/3

We move all terms to the left:

7x/4-((8x+2)/3)=0

We calculate fractions


21x^2/()+(-((8x+2)*4)/()=0



We calculate terms in parentheses: +(-((8x+2)*4)/(), so:

-((8x+2)*4)/(

We multiply all the terms by the denominator


-((8x+2)*4)



We calculate terms in parentheses: -((8x+2)*4), so:

(8x+2)*4

We multiply parentheses

32x+8

Back to the equation:

-(32x+8)



We get rid of parentheses

-32x-8

Back to the equation:

+(-32x-8)



We get rid of parentheses

21x^2/()-32x-8=0

We multiply all the terms by the denominator


21x^2-32x*()-8*()=0

We add all the numbers together, and all the variables

21x^2-32x*()=0

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