7x-x=-36+18x2+18

Solution for 7x-x=-36+18x2+18 equation:

7x-x=-36+18x^2+18

We move all terms to the left:

7x-x-(-36+18x^2+18)=0

We add all the numbers together, and all the variables

-(-36+18x^2+18)+6x=0

We get rid of parentheses

-18x^2+6x+36-18=0

We add all the numbers together, and all the variables

-18x^2+6x+18=0

a = -18; b = 6; c = +18;
Δ = b2-4ac
Δ = 62-4·(-18)·18
Δ = 1332
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1332}=\sqrt{36*37}=\sqrt{36}*\sqrt{37}=6\sqrt{37}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6\sqrt{37}}{2*-18}=\frac{-6-6\sqrt{37}}{-36}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6\sqrt{37}}{2*-18}=\frac{-6+6\sqrt{37}}{-36}
$