7x-8/4x=9/4-5/x

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Solution for 7x-8/4x=9/4-5/x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

7*x-((8/4)*x) = 9/4-(5/x) // - 9/4-(5/x)

7*x-((8/4)*x)+5/x-(9/4) = 0

7*x-2*x+5/x-9/4 = 0

5*x^1+5*x^-1-9/4*x^0 = 0

(5*x^2-9/4*x^1+5*x^0)/(x^1) = 0 // * x^2

x^1*(5*x^2-9/4*x^1+5*x^0) = 0

x^1

5*x^2+(-9/4)*x+5 = 0

5*x^2+(-9/4)*x+5 = 0

DELTA = (-9/4)^2-(4*5*5)

DELTA = -1519/16

DELTA < 0

x in { } 

x belongs to the empty set

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