7x-7+1+x=4+5(x-2)

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Solution for 7x-7+1+x=4+5(x-2) equation: 



7x-7+1+x=4+5(x-2)

We move all terms to the left:

7x-7+1+x-(4+5(x-2))=0

We add all the numbers together, and all the variables

8x-(4+5(x-2))-6=0



We calculate terms in parentheses: -(4+5(x-2)), so:

4+5(x-2)

determiningTheFunctionDomain
5(x-2)+4

We multiply parentheses

5x-10+4

We add all the numbers together, and all the variables

5x-6

Back to the equation:

-(5x-6)



We get rid of parentheses

8x-5x+6-6=0

We add all the numbers together, and all the variables

3x=0

x=0/3

x=0

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