7x-4x(x-3)=48

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Solution for 7x-4x(x-3)=48 equation: 



7x-4x(x-3)=48

We move all terms to the left:

7x-4x(x-3)-(48)=0

We multiply parentheses

-4x^2+7x+12x-48=0

We add all the numbers together, and all the variables

-4x^2+19x-48=0

a = -4; b = 19; c = -48;
Δ = b2-4ac
Δ = 192-4·(-4)·(-48)
Δ = -407
Delta is less than zero, so there is no solution for the equation

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