7x-40-x=-7x+80-3x

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Solution for 7x-40-x=-7x+80-3x equation: 



7x-40-x=-7x+80-3x

We move all terms to the left:

7x-40-x-(-7x+80-3x)=0

We add all the numbers together, and all the variables

7x-x-(-10x+80)-40=0

We add all the numbers together, and all the variables

6x-(-10x+80)-40=0

We get rid of parentheses

6x+10x-80-40=0

We add all the numbers together, and all the variables

16x-120=0

We move all terms containing x to the left, all other terms to the right

16x=120

x=120/16

x=7+1/2

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