7x-4(x+4)=4(3-x)

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Solution for 7x-4(x+4)=4(3-x) equation: 



7x-4(x+4)=4(3-x)

We move all terms to the left:

7x-4(x+4)-(4(3-x))=0

We add all the numbers together, and all the variables

7x-4(x+4)-(4(-1x+3))=0

We multiply parentheses

7x-4x-(4(-1x+3))-16=0



We calculate terms in parentheses: -(4(-1x+3)), so:

4(-1x+3)

We multiply parentheses

-4x+12

Back to the equation:

-(-4x+12)



We add all the numbers together, and all the variables

3x-(-4x+12)-16=0

We get rid of parentheses

3x+4x-12-16=0

We add all the numbers together, and all the variables

7x-28=0

We move all terms containing x to the left, all other terms to the right

7x=28

x=28/7

x=4

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