7x-4(2x-5)=3(x-4)+8

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Solution for 7x-4(2x-5)=3(x-4)+8 equation: 



7x-4(2x-5)=3(x-4)+8

We move all terms to the left:

7x-4(2x-5)-(3(x-4)+8)=0

We multiply parentheses

7x-8x-(3(x-4)+8)+20=0



We calculate terms in parentheses: -(3(x-4)+8), so:

3(x-4)+8

We multiply parentheses

3x-12+8

We add all the numbers together, and all the variables

3x-4

Back to the equation:

-(3x-4)



We add all the numbers together, and all the variables

-1x-(3x-4)+20=0

We get rid of parentheses

-1x-3x+4+20=0

We add all the numbers together, and all the variables

-4x+24=0

We move all terms containing x to the left, all other terms to the right

-4x=-24

x=-24/-4

x=+6

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