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7x-3=6/6x
We move all terms to the left:
7x-3-(6/6x)=0
Domain of the equation: 6x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
7x-(+6/6x)-3=0
We get rid of parentheses
7x-6/6x-3=0
We multiply all the terms by the denominator
7x*6x-3*6x-6=0
Wy multiply elements
42x^2-18x-6=0
a = 42; b = -18; c = -6;
Δ = b2-4ac
Δ = -182-4·42·(-6)
Δ = 1332
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1332}=\sqrt{36*37}=\sqrt{36}*\sqrt{37}=6\sqrt{37}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-6\sqrt{37}}{2*42}=\frac{18-6\sqrt{37}}{84} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+6\sqrt{37}}{2*42}=\frac{18+6\sqrt{37}}{84} $
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