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7x-3(x-2)=2(2x+3)
We move all terms to the left:
7x-3(x-2)-(2(2x+3))=0
We multiply parentheses
7x-3x-(2(2x+3))+6=0
We calculate terms in parentheses: -(2(2x+3)), so:We add all the numbers together, and all the variables
2(2x+3)
We multiply parentheses
4x+6
Back to the equation:
-(4x+6)
4x-(4x+6)+6=0
We get rid of parentheses
4x-4x-6+6=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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