7x-3(2x-5)=2(x+4)+9

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Solution for 7x-3(2x-5)=2(x+4)+9 equation: 



7x-3(2x-5)=2(x+4)+9

We move all terms to the left:

7x-3(2x-5)-(2(x+4)+9)=0

We multiply parentheses

7x-6x-(2(x+4)+9)+15=0



We calculate terms in parentheses: -(2(x+4)+9), so:

2(x+4)+9

We multiply parentheses

2x+8+9

We add all the numbers together, and all the variables

2x+17

Back to the equation:

-(2x+17)



We add all the numbers together, and all the variables

x-(2x+17)+15=0

We get rid of parentheses

x-2x-17+15=0

We add all the numbers together, and all the variables

-1x-2=0

We move all terms containing x to the left, all other terms to the right

-x=2

x=2/-1

x=-2

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