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7x-3(2x-4)x=5x
We move all terms to the left:
7x-3(2x-4)x-(5x)=0
We add all the numbers together, and all the variables
2x-3(2x-4)x=0
We multiply parentheses
-6x^2+2x+12x=0
We add all the numbers together, and all the variables
-6x^2+14x=0
a = -6; b = 14; c = 0;
Δ = b2-4ac
Δ = 142-4·(-6)·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-14}{2*-6}=\frac{-28}{-12} =2+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+14}{2*-6}=\frac{0}{-12} =0 $
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