7x-20=2x-3(3x+12)

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Solution for 7x-20=2x-3(3x+12) equation: 



7x-20=2x-3(3x+12)

We move all terms to the left:

7x-20-(2x-3(3x+12))=0



We calculate terms in parentheses: -(2x-3(3x+12)), so:

2x-3(3x+12)

We multiply parentheses

2x-9x-36

We add all the numbers together, and all the variables

-7x-36

Back to the equation:

-(-7x-36)



We get rid of parentheses

7x+7x+36-20=0

We add all the numbers together, and all the variables

14x+16=0

We move all terms containing x to the left, all other terms to the right

14x=-16

x=-16/14

x=-1+1/7

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