7x-2(x-12)=-5-2(1-3x)

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Solution for 7x-2(x-12)=-5-2(1-3x) equation: 



7x-2(x-12)=-5-2(1-3x)

We move all terms to the left:

7x-2(x-12)-(-5-2(1-3x))=0

We add all the numbers together, and all the variables

7x-2(x-12)-(-5-2(-3x+1))=0

We multiply parentheses

7x-2x-(-5-2(-3x+1))+24=0



We calculate terms in parentheses: -(-5-2(-3x+1)), so:

-5-2(-3x+1)

determiningTheFunctionDomain
-2(-3x+1)-5

We multiply parentheses

6x-2-5

We add all the numbers together, and all the variables

6x-7

Back to the equation:

-(6x-7)



We add all the numbers together, and all the variables

5x-(6x-7)+24=0

We get rid of parentheses

5x-6x+7+24=0

We add all the numbers together, and all the variables

-1x+31=0

We move all terms containing x to the left, all other terms to the right

-x=-31

x=-31/-1

x=+31

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