7x-2(x+3)=3(2x+1)

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Solution for 7x-2(x+3)=3(2x+1) equation: 



7x-2(x+3)=3(2x+1)

We move all terms to the left:

7x-2(x+3)-(3(2x+1))=0

We multiply parentheses

7x-2x-(3(2x+1))-6=0



We calculate terms in parentheses: -(3(2x+1)), so:

3(2x+1)

We multiply parentheses

6x+3

Back to the equation:

-(6x+3)



We add all the numbers together, and all the variables

5x-(6x+3)-6=0

We get rid of parentheses

5x-6x-3-6=0

We add all the numbers together, and all the variables

-1x-9=0

We move all terms containing x to the left, all other terms to the right

-x=9

x=9/-1

x=-9

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