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7x-2(3x+1)=2(2-x)
We move all terms to the left:
7x-2(3x+1)-(2(2-x))=0
We add all the numbers together, and all the variables
7x-2(3x+1)-(2(-1x+2))=0
We multiply parentheses
7x-6x-(2(-1x+2))-2=0
We calculate terms in parentheses: -(2(-1x+2)), so:We add all the numbers together, and all the variables
2(-1x+2)
We multiply parentheses
-2x+4
Back to the equation:
-(-2x+4)
x-(-2x+4)-2=0
We get rid of parentheses
x+2x-4-2=0
We add all the numbers together, and all the variables
3x-6=0
We move all terms containing x to the left, all other terms to the right
3x=6
x=6/3
x=2
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