7x-2(2-3x)=4(x-5)-29

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Solution for 7x-2(2-3x)=4(x-5)-29 equation: 



7x-2(2-3x)=4(x-5)-29

We move all terms to the left:

7x-2(2-3x)-(4(x-5)-29)=0

We add all the numbers together, and all the variables

7x-2(-3x+2)-(4(x-5)-29)=0

We multiply parentheses

7x+6x-(4(x-5)-29)-4=0



We calculate terms in parentheses: -(4(x-5)-29), so:

4(x-5)-29

We multiply parentheses

4x-20-29

We add all the numbers together, and all the variables

4x-49

Back to the equation:

-(4x-49)



We add all the numbers together, and all the variables

13x-(4x-49)-4=0

We get rid of parentheses

13x-4x+49-4=0

We add all the numbers together, and all the variables

9x+45=0

We move all terms containing x to the left, all other terms to the right

9x=-45

x=-45/9

x=-5

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