7x-2(2-3x)=3(x-5)-49

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Solution for 7x-2(2-3x)=3(x-5)-49 equation: 



7x-2(2-3x)=3(x-5)-49

We move all terms to the left:

7x-2(2-3x)-(3(x-5)-49)=0

We add all the numbers together, and all the variables

7x-2(-3x+2)-(3(x-5)-49)=0

We multiply parentheses

7x+6x-(3(x-5)-49)-4=0



We calculate terms in parentheses: -(3(x-5)-49), so:

3(x-5)-49

We multiply parentheses

3x-15-49

We add all the numbers together, and all the variables

3x-64

Back to the equation:

-(3x-64)



We add all the numbers together, and all the variables

13x-(3x-64)-4=0

We get rid of parentheses

13x-3x+64-4=0

We add all the numbers together, and all the variables

10x+60=0

We move all terms containing x to the left, all other terms to the right

10x=-60

x=-60/10

x=-6

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