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7x-1/2x=0
Domain of the equation: 2x!=0We multiply all the terms by the denominator
x!=0/2
x!=0
x∈R
7x*2x-1=0
Wy multiply elements
14x^2-1=0
a = 14; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·14·(-1)
Δ = 56
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{56}=\sqrt{4*14}=\sqrt{4}*\sqrt{14}=2\sqrt{14}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{14}}{2*14}=\frac{0-2\sqrt{14}}{28} =-\frac{2\sqrt{14}}{28} =-\frac{\sqrt{14}}{14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{14}}{2*14}=\frac{0+2\sqrt{14}}{28} =\frac{2\sqrt{14}}{28} =\frac{\sqrt{14}}{14} $
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