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7x-(x-3)=3x+3(x+1)
We move all terms to the left:
7x-(x-3)-(3x+3(x+1))=0
We get rid of parentheses
7x-x-(3x+3(x+1))+3=0
We calculate terms in parentheses: -(3x+3(x+1)), so:We add all the numbers together, and all the variables
3x+3(x+1)
We multiply parentheses
3x+3x+3
We add all the numbers together, and all the variables
6x+3
Back to the equation:
-(6x+3)
6x-(6x+3)+3=0
We get rid of parentheses
6x-6x-3+3=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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