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7x-(x-12)=2x-(-7+x)
We move all terms to the left:
7x-(x-12)-(2x-(-7+x))=0
We add all the numbers together, and all the variables
7x-(x-12)-(2x-(x-7))=0
We get rid of parentheses
7x-x-(2x-(x-7))+12=0
We calculate terms in parentheses: -(2x-(x-7)), so:We add all the numbers together, and all the variables
2x-(x-7)
We get rid of parentheses
2x-x+7
We add all the numbers together, and all the variables
x+7
Back to the equation:
-(x+7)
6x-(x+7)+12=0
We get rid of parentheses
6x-x-7+12=0
We add all the numbers together, and all the variables
5x+5=0
We move all terms containing x to the left, all other terms to the right
5x=-5
x=-5/5
x=-1
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