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7x-(x+3)=3(2x-1)
We move all terms to the left:
7x-(x+3)-(3(2x-1))=0
We get rid of parentheses
7x-x-(3(2x-1))-3=0
We calculate terms in parentheses: -(3(2x-1)), so:We add all the numbers together, and all the variables
3(2x-1)
We multiply parentheses
6x-3
Back to the equation:
-(6x-3)
6x-(6x-3)-3=0
We get rid of parentheses
6x-6x+3-3=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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