7x-(4x-3(x-1))=x+12

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Solution for 7x-(4x-3(x-1))=x+12 equation: 



7x-(4x-3(x-1))=x+12

We move all terms to the left:

7x-(4x-3(x-1))-(x+12)=0

We get rid of parentheses

7x-(4x-3(x-1))-x-12=0



We calculate terms in parentheses: -(4x-3(x-1)), so:

4x-3(x-1)

We multiply parentheses

4x-3x+3

We add all the numbers together, and all the variables

x+3

Back to the equation:

-(x+3)



We add all the numbers together, and all the variables

6x-(x+3)-12=0

We get rid of parentheses

6x-x-3-12=0

We add all the numbers together, and all the variables

5x-15=0

We move all terms containing x to the left, all other terms to the right

5x=15

x=15/5

x=3

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