7x-(3x+5)-8=1/2-7x+5-(8x+20

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Solution for 7x-(3x+5)-8=1/2-7x+5-(8x+20 equation: 



7x-(3x+5)-8=1/2-7x+5-(8x+20

We move all terms to the left:

7x-(3x+5)-8-(1/2-7x+5-(8x+20)=0



Domain of the equation: 2-7x+5-(8x+20)-8!=0

We move all terms containing x to the left, all other terms to the right

-7x-(8x+20)!=1

x∈R



We get rid of parentheses

7x-3x-(1/2-7x+5-(8x+20)-8-5=0

We multiply all the terms by the denominator


7x*2-7x-(8x+20)-3x*2-7x-(8x+20)+5-8-5+5-8-5-(1=0

We add all the numbers together, and all the variables

-14x+7x*2-(8x+20)-3x*2-(8x+20)=0

Wy multiply elements

-14x+14x-(8x+20)-6x-(8x+20)=0

We get rid of parentheses

-14x+14x-8x-6x-8x-20-20=0

We add all the numbers together, and all the variables

-22x-40=0

We move all terms containing x to the left, all other terms to the right

-22x=40

x=40/-22

x=-1+9/11

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