7x-(3x+5)-8=1/2(8x+20)-7x+5)

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Solution for 7x-(3x+5)-8=1/2(8x+20)-7x+5) equation: 



7x-(3x+5)-8=1/2(8x+20)-7x+5)

We move all terms to the left:

7x-(3x+5)-8-(1/2(8x+20)-7x+5))=0



Domain of the equation: 2(8x+20)-7x+5))-8!=0

x∈R



We get rid of parentheses

7x-3x-(1/2(8x+20)-7x+5))-8-5=0

We multiply all the terms by the denominator


7x*2(8x+20)-7x+5))-8-5-3x*2(8x+20)-7x+5))-8-5-(1=0

We add all the numbers together, and all the variables

-7x+7x*2(8x+20)+5))-8-5-3x*2(8x+20)-7x+5))-8-5-(1=0

Wy multiply elements

14x^2(8+5))-8-5-3x*2(8x-7x+20)-7x+5))-8-5-(1=0

We add all the numbers together, and all the variables

14x^213)-8-5-3x*2(x+20)-7x+5))-8-5-(1=0

We do not support expression: x^213

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