7x-(3x+5)-8=1/2(8x+20

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Solution for 7x-(3x+5)-8=1/2(8x+20 equation: 



7x-(3x+5)-8=1/2(8x+20

We move all terms to the left:

7x-(3x+5)-8-(1/2(8x+20)=0



Domain of the equation: 2(8x+20)-8!=0

We move all terms containing x to the left, all other terms to the right

2(8x+20)!=8

x∈R



We get rid of parentheses

7x-3x-(1/2(8x+20)-8-5=0

We multiply all the terms by the denominator


7x*2(8x+20)-3x*2(8x+20)-8-5-8-5-(1=0

We add all the numbers together, and all the variables

7x*2(8x+20)-3x*2(8x+20)=0

Wy multiply elements

14x^2(8-6x^2(8=0

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