7x+8(x+1/4)=3(6x-6)-10

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Solution for 7x+8(x+1/4)=3(6x-6)-10 equation: 



7x+8(x+1/4)=3(6x-6)-10

We move all terms to the left:

7x+8(x+1/4)-(3(6x-6)-10)=0

We add all the numbers together, and all the variables

7x+8(+x+1/4)-(3(6x-6)-10)=0

We multiply parentheses

7x+8x-(3(6x-6)-10)+1/4*8=0

We multiply all the terms by the denominator


7x*4*8+8x*4*8-((3(6x-6)-10))*4*8+1=0

Wy multiply elements

224x*8+256x*8-((3(6x-6)-10))*4*8+1=0

Wy multiply elements

1792x+2048x-((3(6x-6)-10))*4*8+1=0

We add all the numbers together, and all the variables

3840x-((3(6x-6)-10))*4*8+1=0

We move all terms containing x to the left, all other terms to the right

3840x-((3(6x-6)-10))*4*8=-1

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