7x+7=2(3x+3)+1+x

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Solution for 7x+7=2(3x+3)+1+x equation: 



7x+7=2(3x+3)+1+x

We move all terms to the left:

7x+7-(2(3x+3)+1+x)=0



We calculate terms in parentheses: -(2(3x+3)+1+x), so:

2(3x+3)+1+x

determiningTheFunctionDomain
2(3x+3)+x+1

We add all the numbers together, and all the variables

x+2(3x+3)+1

We multiply parentheses

x+6x+6+1

We add all the numbers together, and all the variables

7x+7

Back to the equation:

-(7x+7)



We get rid of parentheses

7x-7x-7+7=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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