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7x+5=3(2x+3)+x-4
We move all terms to the left:
7x+5-(3(2x+3)+x-4)=0
We calculate terms in parentheses: -(3(2x+3)+x-4), so:We get rid of parentheses
3(2x+3)+x-4
We add all the numbers together, and all the variables
x+3(2x+3)-4
We multiply parentheses
x+6x+9-4
We add all the numbers together, and all the variables
7x+5
Back to the equation:
-(7x+5)
7x-7x-5+5=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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