7x+40+3x+112=540

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Solution for 7x+40+3x+112=540 equation: 



7x+40+3x+112=540

We move all terms to the left:

7x+40+3x+112-(540)=0

We add all the numbers together, and all the variables

10x-388=0

We move all terms containing x to the left, all other terms to the right

10x=388

x=388/10

x=38+4/5

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