7x+4+x=4(x-2)+3x

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Solution for 7x+4+x=4(x-2)+3x equation: 



7x+4+x=4(x-2)+3x

We move all terms to the left:

7x+4+x-(4(x-2)+3x)=0

We add all the numbers together, and all the variables

8x-(4(x-2)+3x)+4=0



We calculate terms in parentheses: -(4(x-2)+3x), so:

4(x-2)+3x

We add all the numbers together, and all the variables

3x+4(x-2)

We multiply parentheses

3x+4x-8

We add all the numbers together, and all the variables

7x-8

Back to the equation:

-(7x-8)



We get rid of parentheses

8x-7x+8+4=0

We add all the numbers together, and all the variables

x+12=0

We move all terms containing x to the left, all other terms to the right

x=-12

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